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How to style rows and cells conditionally based on data in GridTreeControl
1 min read
You can apply the style for the rows and cells based on some conditions by using the QueryCellInfo event like below,
Style for Rows:
C#
void treeGrid_ModelLoaded(object sender, EventArgs e)
{
treeGrid.Model.QueryCellInfo += Model_QueryCellInfo;
}
void Model_QueryCellInfo(object sender, GridQueryCellInfoEventArgs e)
{
int nodeindex = treeGrid.InternalGrid.ResolveIndexToColumnIndex(e.Style.ColumnIndex);
if (nodeindex > -1)
{
//Get the node
var node = treeGrid.InternalGrid.GetNodeAtRowIndex(e.Style.RowIndex);
if (node != null)
{
var item = node.Item as EmployeeInfo;
if (item != null)
if (item.EmpID == 1002)
e.Style.Background = Brushes.Red;
else if(item.EmpID==1004)
e.Style.Background = Brushes.Blue;
else if (item.EmpID == 1012)
e.Style.Background = Brushes.Yellow;
else if (item.EmpID == 1005)
e.Style.Background = Brushes.Orange;
}
}
}
Figure 1: Conditional formatting for rows in GridTreeControl
Style for Cells:
C#
void treeGrid_ModelLoaded(object sender, EventArgs e)
{
treeGrid.Model.QueryCellInfo += Model_QueryCellInfo;
}
void Model_QueryCellInfo(object sender, GridQueryCellInfoEventArgs e)
{
int nodeindex = treeGrid.InternalGrid.ResolveIndexToColumnIndex(e.Style.ColumnIndex);
if (nodeindex > -1)
{
if (treeGrid.Columns[nodeindex].MappingName != "EmpID")
return;
else
{
//Get the node
var node = treeGrid.InternalGrid.GetNodeAtRowIndex(e.Style.RowIndex);
if (node != null)
{
var item = node.Item as EmployeeInfo;
if (item != null)
if (item.EmpID == 1002)
e.Style.Background = Brushes.Red;
else if (item.EmpID == 1004)
e.Style.Background = Brushes.Blue;
else if (item.EmpID == 1012)
e.Style.Background = Brushes.Yellow;
else if (item.EmpID == 1005)
e.Style.Background = Brushes.Orange;
}
}
}
}
Figure 2: Conditional formatting for cells in GridTreeControl